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Internet Message Format | 1996-08-05 | 1.0 KB

Path: doors.informatik.uni-siegen.de!plrunu
From: [e-mail] (Runu Knips)
Newsgroups: comp.lang.c,comp.lang.c++
Subject: Re: HELP! On how to declare large arrays.
Date: 15 Mar 1996 13:04:33 GMT
Organization: University of Siegen
Sender: [e-mail] (Runu Knips)
Message-ID: <4ibpt1$[e-mail]>
References: <[e-mail]> <4ib40n$[e-mail]>
NNTP-Posting-Host: doors.informatik.uni-siegen.de

Well, easy. You're using C/C++, so you can declare your array the following way:
(assuming you're using int. Replace it with any other data type if you want)

    int *arr[512];

Now construct the array with:

        for (int i = 512; i--;)
        arr[i] = new int[128];

You can now use exactly the same syntax to access any array element in the
array as if you had declared the array as int arr[512][128];

Nevertheless, you may want to use a #ifdef __MSDOS__ or such, for this
solution is a little bit slower than the 2-dim array solution.

Ciao, Runu.